QED
Linear Algebra · step 12 of 13

Dot product, norms & angles

The dot product u·v = Σuᵢvᵢ also equals |u||v|cos θ, which is what makes it geometric: it is zero exactly when the vectors are perpendicular, positive for acute angles and negative for obtuse. The norm |v| = √(v·v) generalises length, and the Cauchy–Schwarz inequality |u·v| ≤ |u||v| is what guarantees the cosine formula makes sense.

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Method: how to approach it

The order below is what examiners expect to see, and each step carries its own marks.

  1. Compute the dot product componentwiseMultiply matching components and add. The result is a scalar, not a vector.
  2. Compute the norms|v| = √(v₁² + v₂² + …). Keep them in surd form for exact answers.
  3. Solve for the anglecos θ = (u·v)/(|u||v|), then θ = arccos of that. The value always lies in [−1, 1] by Cauchy–Schwarz.
  4. Read off perpendicularityu·v = 0 means orthogonal. This is the quickest test and needs no norms at all.

Worked example

Find the angle between u = (1, 2, 2) and v = (2, 0, 1).

  1. u·v = 1·2 + 2·0 + 2·1 = 4.
  2. |u| = √(1 + 4 + 4) = 3.
  3. |v| = √(4 + 0 + 1) = √5.
  4. cos θ = 4/(3√5) ≈ 0.5963.

Answer. θ = arccos(4/(3√5)) ≈ 53.4°.

Where marks get dropped

These are the specific errors that cost credit on dot product, norms & angles questions — QED's rubric penalises each of them separately.

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Dot product, norms & angles — frequently asked questions

What does a negative dot product mean?

The angle is obtuse — the vectors point in broadly opposite directions. Zero means perpendicular, positive means acute.

What is Cauchy–Schwarz good for?

It guarantees |u·v|/(|u||v|) lies in [−1,1] so the arccos is defined, and it is the source of the triangle inequality |u+v| ≤ |u| + |v|.

How does this generalise?

Any inner product on a vector space — including ∫f g for functions — gives norms, angles and orthogonality. Fourier series are exactly an orthogonal decomposition in such a space.

The rest of Linear Algebra

Matrices, systems, determinants, eigenvalues. Each subtopic below has its own method, worked example and mark-losing traps.

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